-20x+32=-2x^2

Solution for -20x+32=-2x^2 equation:

-20x+32=-2x^2

We move all terms to the left:

-20x+32-(-2x^2)=0

We get rid of parentheses

2x^2-20x+32=0

a = 2; b = -20; c = +32;
Δ = b2-4ac
Δ = -202-4·2·32
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-12}{2*2}=\frac{8}{4}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+12}{2*2}=\frac{32}{4}
=8
$